(y+4)(2y^2+3y-5)=

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Solution for (y+4)(2y^2+3y-5)= equation:


Simplifying
(y + 4)(2y2 + 3y + -5) = 0

Reorder the terms:
(4 + y)(2y2 + 3y + -5) = 0

Reorder the terms:
(4 + y)(-5 + 3y + 2y2) = 0

Multiply (4 + y) * (-5 + 3y + 2y2)
(4(-5 + 3y + 2y2) + y(-5 + 3y + 2y2)) = 0
((-5 * 4 + 3y * 4 + 2y2 * 4) + y(-5 + 3y + 2y2)) = 0
((-20 + 12y + 8y2) + y(-5 + 3y + 2y2)) = 0
(-20 + 12y + 8y2 + (-5 * y + 3y * y + 2y2 * y)) = 0
(-20 + 12y + 8y2 + (-5y + 3y2 + 2y3)) = 0

Reorder the terms:
(-20 + 12y + -5y + 8y2 + 3y2 + 2y3) = 0

Combine like terms: 12y + -5y = 7y
(-20 + 7y + 8y2 + 3y2 + 2y3) = 0

Combine like terms: 8y2 + 3y2 = 11y2
(-20 + 7y + 11y2 + 2y3) = 0

Solving
-20 + 7y + 11y2 + 2y3 = 0

Solving for variable 'y'.

The solution to this equation could not be determined.

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